Quantcast
Channel: Active questions tagged real-analysis - Mathematics Stack Exchange
Viewing all articles
Browse latest Browse all 9155

An example for converse of a theorem in Rudin

$
0
0

A theorem of Rudin's real and complex analysissuppose $\mu$ and $\nu_1$,$\nu_2$ are measures on a $\sigma$_algebra m, and $\mu$ is positive:

if $\nu_1<<\mu$ and $\nu_2\perp\mu$, then $\nu_1\perp\nu_2$ .

I would like to the converse of this theorem, for that matter, give an example.I have tried but unfortunately I could not do it. Any hints would be appreciated.


Viewing all articles
Browse latest Browse all 9155

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>