Find $\lim_{n\to \infty }\left(2n^{1/n}-1\right)^n/n^2$.
I can use L'Hospital rule and differentiate it two times. But is there a simple way to solve this?
↧
Find $\lim_{n\to \infty }\frac{\left(2n^{1/n}-1\right)^n}{n^2}$ [duplicate]
↧