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Asymptotics for $f(z) = (z-1) \prod_n \frac{2}{z^{1/a_n}+1}$ with $1/a_1 + 1/a_2 + 1/a_3 + ... = 1.$

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Let $Re(z) > 1$

Consider functions such as

$$f(z) = (z-1) ([2 / (z^{1/a_1} + 1)] [2 / (z^{1/a_2} + 1)][2 / (z^{1/a_3} + 1)][2 / (z^{1/a_4} + 1)][2 / (z^{1/a_5} + 1)]...)$$

or more formally

$$f(z) = (z-1) \prod_n \frac{2}{z^{1/a_n}+1}$$

Where

$$1/a_1 + 1/a_2 + 1/a_3 + ... = 1.$$

and $a_n$ is a rising integer sequence.

Now clearly this function does not grow like any power of $x$.

For instance if $a_n = 2^n$ we get $f(z) = \ln(z)$.

So what are the good asymptotics of $f(z)$ ?

Let $\pi(n)$ be the counting function of integers $a_n$ between $0$ and $n$.

Then it seems a good estimate for $f(z)$ when $z$ is close to the positive real line is

$$f(z) = \exp(C \pi(\ln(z)))$$

For some value $C$.

Is this correct ? And how good is it exactly ?

For instance if $a_n = n(n+1)$ do we get

$$f(z) = O(\exp(\sqrt\ln(z))) $$?

And if $a_n$ is sylvester's sequence do we get

$$f(z) = O(\exp(C \pi(\ln(z))))$$

where $\pi$ counts the sylvester numbers ?


For instance let $z = \exp(400)$

and let $a_n = n(n+1)$.

Then $f(z) = \exp(q)$

where $20 < q < 21$.

thereby supporting the estimate

$$f(z) = O(\exp(\sqrt\ln(z))) $$



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