$$\limsup_{n\to\infty} \sin(√3n\pi)$$I know that sin function is bounded between -1 and 1. But does is straight away imply that the limsup is 1 or is there any different way to solve this.
Also if $$\limsup_{n\to\infty} \sin((1/√3) n\pi)$$is also same or different.