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Why does the measurable uniformization property imply all sets are measurable?

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In The strength of measurability hypotheses, Raisonnier and Stern formulated the following principle:

(MUP). For any family $(A_x)_{x\in B}$ of non-empty subsets of$2^\omega$, indexed by the elements of a set $B$ of positive measure,there is a Borel function $f$, such that $\{x\in B\mid f(x)\notin A_x\}$ has Lebesgue measure zero.

They proceed to note that MUP implies the measurability of all sets. The argument: "in order to prove the measurability of $A$, one just uniformizes its characteristic function."

My question is: what does this mean? The characteristic function $\chi_A$ of $A$ is a subset of $(2^\omega)^2$, but I don't see how uniformizing it can get us anywhere (or needs the MUP to begin with). So it would seem I am missing something obvious.


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