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equality of inner product and derivative

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I came across the following claim

$$\lim_{r \to 0} \dfrac{f(rx) - f(0)}{r} = \langle v,x \rangle$$

locally uniformly implies that the derivative of $f$ at $0$ exists and $Df(0) = v$.

I don't follow how this holds, the definition of the derivative at $a$ is an operator $Df(a)$ satisfying

$$\lim_{r\to a} \dfrac{|f(r)-f(a)-Df(a)|r-a||}{|a-r|} = 0$$

on the other hand,

$$\langle v,x \rangle = |v| |x| \cos \theta$$

What am I missing?


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