Let $f : \mathbb{R} → \mathbb{R}$ be differentiable at $x = 0$. Define $g(x) = f(x^2)$. Show
that $g$ is differentiable at $0 $(by the chain rule).
Let $f : \mathbb{R} → \mathbb{R}$ be differentiable at $x = 0$. Define $g(x) = f(x^2)$. Show
that $g$ is differentiable at $0 $(by the chain rule).