The limit below is solved using multiple methods.$$\lim_{x\to\infty} \frac{x^n}{e^x}$$
However, I am trying to solve it using the comment made below the question:
Only one application of l'Hopital's rule is necessary if you takelogarithms first.
$$\lim_{x\to\infty} \frac{x^n}{e^x}=\lim_{x\to\infty}\exp \left(\ln \frac{x^n}{e^x}\right)=\lim_{x\to\infty}\exp \left(n\ln x-x\right)$$
And now I don't know how to proceed since this is the $\infty-\infty$ case. What am I missing, or was something else meant by the comment?